Question about 'sizeof'

Hello,
I have another simple question about an array in PHP and a variable in
PHP.

This is the array:

$thumbs_cat_1 = array(
'wine',
'cheese',
'ice',
'bread'
);


$thumbs_cat_2 = array(
'hello',
'goodbye'
);


This will work:
$item_total = sizeof($thumbs_cat_1);
output: 4

$item_total = sizeof($thumbs_cat_2);
output: 2


Now, i want to replace the parameter in 'sizeof' by a variable

$thumb = 1;
$item = '$thumbs_cat_' . $thumb; //this outputs a string:
$thumbs_cat_1

$item_total = sizeof($item);
output: Nothing!

How do i pass a variable to the 'sizeof' function?

Thanks
Marco

SM wrote:
> Hello,
> I have another simple question about an array in PHP and a variable in
> PHP.
>
> This is the array:
>
> $thumbs_cat_1 = array(
> 'wine',
> 'cheese',
> 'ice',
> 'bread'
> );
>
>
> $thumbs_cat_2 = array(
> 'hello',
> 'goodbye'
> );
>
>
> This will work:
> $item_total = sizeof($thumbs_cat_1);
> output: 4
>
> $item_total = sizeof($thumbs_cat_2);
> output: 2
>
>
> Now, i want to replace the parameter in 'sizeof' by a variable
>
> $thumb = 1;
> $item = '$thumbs_cat_' . $thumb; //this outputs a string:
> $thumbs_cat_1
>
> $item_total = sizeof($item);
> output: Nothing!
>
> How do i pass a variable to the 'sizeof' function?

You should use variable variable:
$item_total = sizeof($$item);

Mark double $$
This is true in any situation, not only with sizeof

best regards
Piotr N

On May 8, 11:15 am, SM <servandomont...@gmail.com> wrote:
> Hello,
> I have another simple question about an array in PHP and a variable in
> PHP.
>
> This is the array:
>
> $thumbs_cat_1 = array(
> 'wine',
> 'cheese',
> 'ice',
> 'bread'
> );
>
> $thumbs_cat_2 = array(
> 'hello',
> 'goodbye'
> );
>
> This will work:
> $item_total = sizeof($thumbs_cat_1);
> output: 4
>
> $item_total = sizeof($thumbs_cat_2);
> output: 2
>
> Now, i want to replace the parameter in 'sizeof' by a variable
>
> $thumb = 1;
> $item = '$thumbs_cat_' . $thumb; //this outputs a string:
> $thumbs_cat_1
>
> $item_total = sizeof($item);
> output: Nothing!
>
> How do i pass a variable to the 'sizeof' function?
>
> Thanks
> Marco

Marco,

You should be getting a return of 1 (integer) for a string passed to
the count() function. (sizeof is an alias of count)

To get the length of a string, you would traditionally use
strlen($item), which would return the length of a string.

Regards,

Steve

On May 8, 11:36 am, ELINTPimp <smsi...@gmail.com> wrote:
> On May 8, 11:15 am, SM <servandomont...@gmail.com> wrote:
>
>
>
> > Hello,
> > I have another simple question about an array in PHP and a variable in
> > PHP.
>
> > This is the array:
>
> > $thumbs_cat_1 = array(
> > 'wine',
> > 'cheese',
> > 'ice',
> > 'bread'
> > );
>
> > $thumbs_cat_2 = array(
> > 'hello',
> > 'goodbye'
> > );
>
> > This will work:
> > $item_total = sizeof($thumbs_cat_1);
> > output: 4
>
> > $item_total = sizeof($thumbs_cat_2);
> > output: 2
>
> > Now, i want to replace the parameter in 'sizeof' by a variable
>
> > $thumb = 1;
> > $item = '$thumbs_cat_' . $thumb; //this outputs a string:
> > $thumbs_cat_1
>
> > $item_total = sizeof($item);
> > output: Nothing!
>
> > How do i pass a variable to the 'sizeof' function?
>
> > Thanks
> > Marco
>
> Marco,
>
> You should be getting a return of 1 (integer) for a string passed to
> the count() function. (sizeof is an alias of count)
>
> To get the length of a string, you would traditionally use
> strlen($item), which would return the length of a string.
>
> Regards,
>
> Steve

Ahhh, now i understand after reading Pitor's reply. Yes, he is
correct, I read the question differently.

Steve

>> $thumb = 1;
>> $item = '$thumbs_cat_' . $thumb; //this outputs a string:
>> $thumbs_cat_1
>>
>> $item_total = sizeof($item);
>> output: Nothing!
>>
>> How do i pass a variable to the 'sizeof' function?
>
> You should use variable variable:
> $item_total = sizeof($$item);
>
> Mark double $$
> This is true in any situation, not only with sizeof

Forgot about one small detail:
$item = 'thumbs_cat_' . $thumb; //this outputs a string:
---------^ loose the '$';

best regards
Piotr N

On May 8, 11:36 am, ELINTPimp <smsi...@gmail.com> wrote:
> On May 8, 11:15 am, SM <servandomont...@gmail.com> wrote:
>
>
>
> > Hello,
> > I have another simple question about an array in PHP and a variable in
> > PHP.
>
> > This is the array:
>
> > $thumbs_cat_1 = array(
> > 'wine',
> > 'cheese',
> > 'ice',
> > 'bread'
> > );
>
> > $thumbs_cat_2 = array(
> > 'hello',
> > 'goodbye'
> > );
>
> > This will work:
> > $item_total = sizeof($thumbs_cat_1);
> > output: 4
>
> > $item_total = sizeof($thumbs_cat_2);
> > output: 2
>
> > Now, i want to replace the parameter in 'sizeof' by a variable
>
> > $thumb = 1;
> > $item = '$thumbs_cat_' . $thumb; //this outputs a string:
> > $thumbs_cat_1
>
> > $item_total = sizeof($item);
> > output: Nothing!
>
> > How do i pass a variable to the 'sizeof' function?
>
> > Thanks
> > Marco
>
> Marco,
>
> You should be getting a return of 1 (integer) for a string passed to
> the count() function. (sizeof is an alias of count)
>
> To get the length of a string, you would traditionally use
> strlen($item), which would return the length of a string.
>
> Regards,
>
> Steve

I don't need the length of the string , just the actual variable. But
i did like the fact that sizeof is an alias of count. So i will use
count instead.
I didn't know about the $$ tip. Wow! so easy. Thanks, It Works!

Heres the final code:

$thumb = 1;
$item = '$thumbs_cat_' . $thumb;
$item_total = count($item);

Thanks again
Marco

On May 8, 11:42 am, Piotr <s...@poczta.onet.pl> wrote:
> >> $thumb = 1;
> >> $item = '$thumbs_cat_' . $thumb; //this outputs a string:
> >> $thumbs_cat_1
>
> >> $item_total = sizeof($item);
> >> output: Nothing!
>
> >> How do i pass a variable to the 'sizeof' function?
>
> > You should use variable variable:
> > $item_total = sizeof($$item);
>
> > Mark double $$
> > This is true in any situation, not only with sizeof
>
> Forgot about one small detail:
> $item = 'thumbs_cat_' . $thumb; //this outputs a string:
> ---------^ loose the '$';
>
> best regards
> Piotr N

I don't need the length of the string , just the actual variable. But
i did like the fact that sizeof is an alias of count. So i will use
count instead.
I didn't know about the $$ tip. Wow! so easy. Thanks, It Works!

Heres the final code:

$thumb = 1;
$item = 'thumbs_cat_' . $thumb;
$item_total = count($item);

Thanks again
Marco

On May 8, 11:42 am, Piotr <s...@poczta.onet.pl> wrote:
> >> $thumb = 1;
> >> $item = '$thumbs_cat_' . $thumb; //this outputs a string:
> >> $thumbs_cat_1
>
> >> $item_total = sizeof($item);
> >> output: Nothing!
>
> >> How do i pass a variable to the 'sizeof' function?
>
> > You should use variable variable:
> > $item_total = sizeof($$item);
>
> > Mark double $$
> > This is true in any situation, not only with sizeof
>
> Forgot about one small detail:
> $item = 'thumbs_cat_' . $thumb; //this outputs a string:
> ---------^ loose the '$';
>
> best regards
> Piotr N

I don't need the length of the string , just the actual variable. But
i did like the fact that sizeof is an alias of count. So i will use
count instead.
I didn't know about the $$ tip. Wow! so easy. Thanks, It Works!

Heres the final code:

$thumb = 1;
$item = 'thumbs_cat_' . $thumb;
$item_total = count($$item);

Thanks again
Marco

On May 8, 11:50 am, SM <servandomont...@gmail.com> wrote:
> On May 8, 11:42 am, Piotr <s...@poczta.onet.pl> wrote:
>
>
>
> > >> $thumb = 1;
> > >> $item = '$thumbs_cat_' . $thumb; //this outputs a string:
> > >> $thumbs_cat_1
>
> > >> $item_total = sizeof($item);
> > >> output: Nothing!
>
> > >> How do i pass a variable to the 'sizeof' function?
>
> > > You should use variable variable:
> > > $item_total = sizeof($$item);
>
> > > Mark double $$
> > > This is true in any situation, not only with sizeof
>
> > Forgot about one small detail:
> > $item = 'thumbs_cat_' . $thumb; //this outputs a string:
> > ---------^ loose the '$';
>
> > best regards
> > Piotr N
>
> I don't need the length of the string , just the actual variable. But
> i did like the fact that sizeof is an alias of count. So i will use
> count instead.
> I didn't know about the $$ tip. Wow! so easy. Thanks, It Works!
>
> Heres the final code:
>
> $thumb = 1;
> $item = 'thumbs_cat_' . $thumb;
> $item_total = count($$item);
>
> Thanks again
> Marco

Maybe i should open a new post for this one, but here it goes:

I'm stock! When i want to reference that variable in a echo statment,
it does't work. Any suggestions?
Thanks

<li><a href="<?php echo $SERVER['PHP_SELF']; ?>?cat=<?php echo
$category_this; ?>"><img src="images/<?php echo($$item[$i]);?>"
alt="" /></a></li>

SM wrote:
> On May 8, 11:50 am, SM <servandomont...@gmail.com> wrote:
>> On May 8, 11:42 am, Piotr <s...@poczta.onet.pl> wrote:
>>
>>
>>
>>>>> $thumb = 1;
>>>>> $item = '$thumbs_cat_' . $thumb; //this outputs a string:
>>>>> $thumbs_cat_1
>>>>> $item_total = sizeof($item);
>>>>> output: Nothing!
>>>>> How do i pass a variable to the 'sizeof' function?
>>>> You should use variable variable:
>>>> $item_total = sizeof($$item);
>>>> Mark double $$
>>>> This is true in any situation, not only with sizeof
>>> Forgot about one small detail:
>>> $item = 'thumbs_cat_' . $thumb; //this outputs a string:
>>> ---------^ loose the '$';
>>> best regards
>>> Piotr N
>> I don't need the length of the string , just the actual variable. But
>> i did like the fact that sizeof is an alias of count. So i will use
>> count instead.
>> I didn't know about the $$ tip. Wow! so easy. Thanks, It Works!
>>
>> Heres the final code:
>>
>> $thumb = 1;
>> $item = 'thumbs_cat_' . $thumb;
>> $item_total = count($$item);
>>
>> Thanks again
>> Marco
>
> Maybe i should open a new post for this one, but here it goes:
>
> I'm stock! When i want to reference that variable in a echo statment,
> it does't work. Any suggestions?
> Thanks
>
> <li><a href="<?php echo $SERVER['PHP_SELF']; ?>?cat=<?php echo
> $category_this; ?>"><img src="images/<?php echo($$item[$i]);?>"
> alt="" /></a></li>

:)
It should look like this. Mark the { and }
echo ${$item[$i]};

As a side note, is this really best way to access needed data this way ?
Cant you keep original values in the array instead of the variable names ?

best regards
Piotr N