How to calculate the running time

The start and end times for a tv show or film .


17:50
18:30

40 minutes running time

23:50
00:30

40 minutes running time

23:50
01:40

110 minutes running time


While i could write the code in a luddite type of fashion and it would
work fine and stuff - is there a one or two line solution that would do
the same job ? .

Krustov napisał(a):
> The start and end times for a tv show or film .
> 17:50
> 18:30
>
> 40 minutes running time
>
> 23:50
> 00:30
>
> 40 minutes running time
>
> 23:50
> 01:40
>
> 110 minutes running time
>
>
> While i could write the code in a luddite type of fashion and it would
> work fine and stuff - is there a one or two line solution that would do
> the same job ? .

echo (strtotime("18:30")-strtotime("17:50"))/60;
echo (strtotime("+1 days 1:40")-strtotime("23:50"))/60;
at least I don't know any better solution :)

--
Wiktor Walc
http://phpfreelancer.net

<comp.lang.php>
<iktorn>
<Fri, 23 Mar 2007 20:51:52 +0100>
<eu1b3e$85c$1@news.task.gda.pl>

> echo (strtotime("18:30")-strtotime("17:50"))/60;
> echo (strtotime("+1 days 1:40")-strtotime("23:50"))/60;
> at least I don't know any better solution :)
>

At least you gave it crack :-)

18:05
21:10

23:20
01:15

etc

The ideal solution would be one that takes two unknown values to produce
a end result value running time like 100 minutes .

Krustov napisał(a):
> <comp.lang.php>
> <iktorn>
> <Fri, 23 Mar 2007 20:51:52 +0100>
> <eu1b3e$85c$1@news.task.gda.pl>
>
>> echo (strtotime("18:30")-strtotime("17:50"))/60;
>> echo (strtotime("+1 days 1:40")-strtotime("23:50"))/60;
>> at least I don't know any better solution :)
>>
>
> At least you gave it crack :-)
>
> 18:05
> 21:10
>
> 23:20
> 01:15
>
> etc
>
> The ideal solution would be one that takes two unknown values to produce
> a end result value running time like 100 minutes .

function f($start,$end){
return ($start>$end?(strtotime("+1 day
".$end)-strtotime($start)):(strtotime($end)-strtotime($start)))/60;
}

;)

--
Wiktor Walc
http://phpfreelancer.net

<comp.lang.php>
<iktorn>
<Fri, 23 Mar 2007 21:58:38 +0100>
<eu1f0k$ghm$1@news.task.gda.pl>

> > 18:05
> > 21:10
> >
> > 23:20
> > 01:15
> >
> > etc
> >
> > The ideal solution would be one that takes two unknown values to produce
> > a end result value running time like 100 minutes .
>
> function f($start,$end){
> return ($start>$end?(strtotime("+1 day
> ".$end)-strtotime($start)):(strtotime($end)-strtotime($start)))/60;
> }
>

That does the job fine - nice one dude .

iktorn wrote:
> Krustov napisał(a):
>> The start and end times for a tv show or film .
>> 17:50
>> 18:30
>>
>> 40 minutes running time
>>
>> 23:50
>> 00:30
>>
>> 40 minutes running time
>>
>> 23:50
>> 01:40
>>
>> 110 minutes running time
>>
>>
>> While i could write the code in a luddite type of fashion and it would
>> work fine and stuff - is there a one or two line solution that would
>> do the same job ? .
>
> echo (strtotime("18:30")-strtotime("17:50"))/60;
> echo (strtotime("+1 days 1:40")-strtotime("23:50"))/60;
> at least I don't know any better solution :)
>

Or to put everything in one statement, perhaps

echo ((strtotime("+1 days 1:40")-strtotime("23:50"))/60) % (24*60*60);

--
==================
Remove the "x" from my email address
Jerry Stuckle
JDS Computer Training Corp.
jstucklex@attglobal.net
==================

Krustov wrote:

> 23:50
> 01:40
>
> 110 minutes running time

<?php

$start = '23:50';
$end = '01:40';

list($start_h, $start_m) = explode(':', $start);
$start = (60 * $start_h) + $start_m;

list($end_h, $end_m ) = explode(':', $end);
$end = (60 * $end_h) + $end_m;

$length = $end - $start;
if ($length < 0)
$length += 1440;

echo "Length is $length minutes.\n";

?>

--
Toby A Inkster BSc (Hons) ARCS
Contact Me ~ http://tobyinkster.co.uk/contact
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* = I'm getting there!