Variable assignment using OR operator?

Hello,

I would like to set a variable to a default if 2 other vars are undef.
Obviously there are several ways to do this but I would like to do it as I
would in Perl:

$memberState = $_POST['ms'] || $_GET['ms'] || 'Unapproved';

Is there acorrect way to do this in 1 line in PHP?

TIA,

jg

.oO(jerrygarciuh)

>I would like to set a variable to a default if 2 other vars are undef.
>Obviously there are several ways to do this but I would like to do it as I
>would in Perl:
>
>$memberState = $_POST['ms'] || $_GET['ms'] || 'Unapproved';
>
>Is there acorrect way to do this in 1 line in PHP?

$memberState = isset($_REQUEST['ms']) ? $_REQUEST['ms'] : 'Unapproved';

Try if that fits your needs ($_REQUEST contains both POST and GET
variables).

Micha

Thanks!

jg


"Michael Fesser" <netizen@gmx.net> wrote in message
news:8v6n11d2eu33jicglqugge5ngejrrrsiqn@4ax.com...
> .oO(jerrygarciuh)
>
>>I would like to set a variable to a default if 2 other vars are undef.
>>Obviously there are several ways to do this but I would like to do it as I
>>would in Perl:
>>
>>$memberState = $_POST['ms'] || $_GET['ms'] || 'Unapproved';
>>
>>Is there acorrect way to do this in 1 line in PHP?
>
> $memberState = isset($_REQUEST['ms']) ? $_REQUEST['ms'] : 'Unapproved';
>
> Try if that fits your needs ($_REQUEST contains both POST and GET
> variables).
>
> Micha

"jerrygarciuh" <designs@no.spam.nolaflash.com> wrote in message
news:QPMSd.4029$SF.1615@lakeread08...
: Hello,
:
: I would like to set a variable to a default if 2 other vars are undef.
: Obviously there are several ways to do this but I would like to do it as I
: would in Perl:
:
: $memberState = $_POST['ms'] || $_GET['ms'] || 'Unapproved';
:
: Is there acorrect way to do this in 1 line in PHP?
:

I believe it would work just like that, you might want brackets though:

$memberState = ($_POST['ms'] || $_GET['ms'] || 'Unapproved');

otherwise, you'll get

if (!($memberState = $_POST['ms']))
{
$GET['ms'] or 'Unapproved';
}
which is probably not what you want

Actually that performs as though it is a conditional:

echo $memberState = ($x || $y || 'Unapproved');

outputs 1

Surely there is a construct for this in PHP? Michaels solution, while
helpful in that case does not solve the over all problem of an elegant 1
liner which does this lovely trick.

Thanks for the reply!

jg



"Matt Mitchell" <m_a_t_t_remove_the_underscores@metalsponge.net> wrote in
message news:b1qTd.175304$B8.158991@fe3.news.blueyonder.co .uk...
> "jerrygarciuh" <designs@no.spam.nolaflash.com> wrote in message
> news:QPMSd.4029$SF.1615@lakeread08...
> : Hello,
> :
> : I would like to set a variable to a default if 2 other vars are undef.
> : Obviously there are several ways to do this but I would like to do it as
> I
> : would in Perl:
> :
> : $memberState = $_POST['ms'] || $_GET['ms'] || 'Unapproved';
> :
> : Is there acorrect way to do this in 1 line in PHP?
> :
>
> I believe it would work just like that, you might want brackets though:
>
> $memberState = ($_POST['ms'] || $_GET['ms'] || 'Unapproved');
>
> otherwise, you'll get
>
> if (!($memberState = $_POST['ms']))
> {
> $GET['ms'] or 'Unapproved';
> }
> which is probably not what you want
>
>

jerrygarciuh wrote:

> an elegant 1
> liner which does this lovely trick.

This is just my personal opinion, but since I started writing large
programs that have to be maintainable and understandable to myself and
others, I have really come to dislike 'elegant one liners'.

If I understood your problem correctly, I would simply write this:
(combining $_POST and $_GET in S_REQUEST):


if (isset($_REQUEST['ms']))
$memberState = $_REQUEST['ms'];
else
$memberState = 'Unapproved';


I'd rather have four lines which are immediately obvious than one line
which is a puzzle, however elegant it may be.

But to each his own, YMMV, etc.

JP

--
Sorry, <devnull@cauce.org> is a spam trap.
Real e-mail address unavailable. 5000+ spams per month.