Check String for Digits ?

Hi guys,

I want to validate a string to make sure it contains only digits.

0001 = true
6669 = true
00a0 = false
6.665 = false

What's the best way to go about doing that ?

Take care,
Cyrus

Cyrus D. wrote:
> Hi guys,
>
> I want to validate a string to make sure it contains only digits.
>
> 0001 = true
> 6669 = true
> 00a0 = false
> 6.665 = false
>
> What's the best way to go about doing that ?

Lots of ways to do it.
This is one way: preg_match('/^\d{4,4}$/', $var)

/Bent

Cyrus D. wrote:

> Hi guys,
>
> I want to validate a string to make sure it contains only digits.
>
> 0001 = true
> 6669 = true
> 00a0 = false
> 6.665 = false
>
> What's the best way to go about doing that ?
>
> Take care,
> Cyrus
>
>

preg_match('`^[0-9]+$`',$string);

returns TRUE if *only* digits are in the string, no matter what length
it is.

--
Justin Koivisto - spam@koivi.com
http://www.koivi.com

Cyrus D. wrote:
> I want to validate a string to make sure it contains only digits.
[snip]
> What's the best way to go about doing that ?


I'd use a regular expression:

php$ cat onlydigits.php
<?php
function only_digits($x) {
return !preg_match('/[^0-9]/', $x);
}

if (only_digits('0001')) echo 'OK'; else echo 'BAD'; echo "\n";
if (only_digits('6669')) echo 'OK'; else echo 'BAD'; echo "\n";
if (only_digits('00a0')) echo 'OK'; else echo 'BAD'; echo "\n";
if (only_digits('6.665')) echo 'OK'; else echo 'BAD'; echo "\n";
?>

php$ php onlydigits.php
OK
OK
BAD
BAD



Check the manual @
http://www.php.net/preg_match

--
USENET would be a better place if everybody read:
http://www.expita.com/nomime.html
http://www.netmeister.org/news/learn2quote2.html
http://www.catb.org/~esr/faqs/smart-questions.html

Cyrus D. wrote:
> Hi guys,
>
> I want to validate a string to make sure it contains only digits.
>
> 0001 = true
> 6669 = true
> 00a0 = false
> 6.665 = false
>
> What's the best way to go about doing that ?

An alternative suggestion without regexps:

is_numeric($string) && strval(floor(intval($string))) == $string

Checks if $string is numeric; and then removes possible decimal places and
compares that to the original (to make sure there are no points).

--
Markus

On Wed, 20 Oct 2004, Markus Ernst wrote:

> Cyrus D. wrote:
>> I want to validate a string to make sure it contains only digits.
>
> An alternative suggestion without regexps:
>
> is_numeric($string) && strval(floor(intval($string))) == $string
>
> Checks if $string is numeric; and then removes possible decimal places and
> compares that to the original (to make sure there are no points).

Technically this will also allow strings which begin with "-" or "+", and
those which contain a "." followed solely by zeros. This might be what is
required, though.

--
Matt

Matt Raines wrote:
> On Wed, 20 Oct 2004, Markus Ernst wrote:
>
>> Cyrus D. wrote:
>>> I want to validate a string to make sure it contains only digits.
>>
>> An alternative suggestion without regexps:
>>
>> is_numeric($string) && strval(floor(intval($string))) == $string
>>
>> Checks if $string is numeric; and then removes possible decimal
>> places and compares that to the original (to make sure there are no
>> points).
>
> Technically this will also allow strings which begin with "-" or "+",
> and those which contain a "." followed solely by zeros. This might be
> what is required, though.

Well it is rather a mistake in my thinking... a corrected version:

is_numeric($string) && number_format(abs($string), 0, "", "") === $string

--
Markus