PHP Date Question: How to Determine The Date Each of the Past 3 Sundays

Hello,

How can I determine what the date was (in YYYY-MM-DD format) last
Sunday, and the Sunday before that?

For example:

Today is Thursday, August 18, 2004 (2004-08-18). I would like to have
the following variables:

$this_past_sunday = 2004-08-14
$two_sundays_ago = 2004-08-07
$three_sundays_ago = 2004-07-31

etc. etc.

Thank you very much for your help in figuring this out!

- Eric

Eric,

Clues for you, the rest is up to you to figure out.

This example would determine two dates based on epochs:

$month, $day, $year are up to you.

$this_epoch = date( "U", mktime ( 0,0,0, $month, $day, $year ) );
$next_epoch = $this_epoch + 604800 ;
$next_ts = date( "Y-m-d H:i:s", date ( $next_epoch ) ) ;

Solve:

$last_week_epoch = $this_epoch - ?
$two_weeks_ago_epoch = $this_epoch - ?

Have fun!

-DG-


Eric Linders wrote:
> Hello,
>
> How can I determine what the date was (in YYYY-MM-DD format) last
> Sunday, and the Sunday before that?
>
> For example:
>
> Today is Thursday, August 18, 2004 (2004-08-18). I would like to have
> the following variables:
>
> $this_past_sunday = 2004-08-14
> $two_sundays_ago = 2004-08-07
> $three_sundays_ago = 2004-07-31
>
> etc. etc.
>
> Thank you very much for your help in figuring this out!
>
> - Eric

"Eric Linders" <elinders88@hotmail.com> wrote in message
news:491326e5.0408182004.52f3adf1@posting.google.c om...
> How can I determine what the date was (in YYYY-MM-DD format) last
> Sunday, and the Sunday before that?

See my reply to your other post and you should be able to get it from there.

Steve
--
Steven C. Gallafent - The Computer Guy, Inc.
steve@compguy.com - http://www.compguy.com/

In message <491326e5.0408182004.52f3adf1@posting.google.com >, Eric
Linders <elinders88@hotmail.com> writes
>Hello,
>
>How can I determine what the date was (in YYYY-MM-DD format) last
>Sunday, and the Sunday before that?
>
>For example:
>
>Today is Thursday, August 18, 2004 (2004-08-18). I would like to have
>the following variables:
>
>$this_past_sunday = 2004-08-14
>$two_sundays_ago = 2004-08-07
>$three_sundays_ago = 2004-07-31
>
>etc. etc.
>
>Thank you very much for your help in figuring this out!
>
>- Eric


I would do something like

$7daysInSeconds = 86400 * 7;
$lastSunday = strtotime("last sunday");
$two_sundays_ago = $lastSunday - $7daysInSeconds;
$three_sundays_ago = $two_sundays_ago - $7daysInSeconds;

then format however you like. e.g.
$lastSundayString = date('Y-m-d', $lastSunday) ;
etc...

--
Rob...