why would a directory fail the is_dir() test?

In the function below, before I open the directory I first test to
make sure the address I have is, in fact, a directory. This function
was working fine on one web server running FreeBSD and PHP 4.06.
However, today I'm trying to run this software on a new server (RH
Linux 9, PHP 4.2.3) and the directory is failing the is_dir() test.
The error message that I have in my code is printing out this error:

In getListOfAnyDirectory(), we expected the function to be handed an
address to a directory, but instead we were given this:
ppArrangementsPublic/.


Now, ppArrangementsPublic/ looks like a directory to me. So why is it
failing the test?








function getListOfAnyDirectory($address=false) {
// 03-17-04 - this function should be given an address to a folder.

$controllerForAll = & getController();
$resultsObject = & $controllerForAll->getObject("McResults", " in
getListOfAnyDirectory().");
$theDirFilesArray = array() ;

$address2 = str_replace("/", "", $address);

if (is_dir($address) || is_dir($address2)) {
// open the directory and load all the files into an array
$theDir = @ opendir($address);

if ($theDir) {
// We go through the array one element at a time, putting it into a
new array, minus invisible files
//marked by "." and ".."

while ($theDirFiles = readdir ($theDir)) {
if ($theDirFiles != "." && $theDirFiles != "..") {
$theDirFilesArray[] = $theDirFiles ;
}
}

closedir ($theDir) ;
return $theDirFilesArray;
} else {
$resultsObject->error("In getListOfAnyDirectory(), we tried to open
the directory at the address $address, but for some reason it didn't
open.", "getListOfAnyDirectory");
}
} else {
$resultsObject->error("In getListOfAnyDirectory(), we expected the
function to be handed an address to a directory, but instead we were
given this: $address.", "getListOfAnyDirectory");
}
}

"lawrence" <lkrubner@geocities.com> wrote in message
news:da7e68e8.0404301520.1d60f4c@posting.google.co m...
> In the function below, before I open the directory I first test to
> make sure the address I have is, in fact, a directory. This function
> was working fine on one web server running FreeBSD and PHP 4.06.
> However, today I'm trying to run this software on a new server (RH
> Linux 9, PHP 4.2.3) and the directory is failing the is_dir() test.
> The error message that I have in my code is printing out this error:
>
> In getListOfAnyDirectory(), we expected the function to be handed an
> address to a directory, but instead we were given this:
> ppArrangementsPublic/.
>
>
> Now, ppArrangementsPublic/ looks like a directory to me. So why is it
> failing the test?

<snip>

I can only speculate that your "directory" is not only not a directory, but
doesn't actually exist at all. Does file_exists() return 1? Can you find it
using the shell?

Garp

Regarding this well-known quote, often attributed to lawrence's famous "30
Apr 2004 16:20:44 -0700" speech:

> In the function below, before I open the directory I first test to
> make sure the address I have is, in fact, a directory. This function
> was working fine on one web server running FreeBSD and PHP 4.06.
> However, today I'm trying to run this software on a new server (RH
> Linux 9, PHP 4.2.3) and the directory is failing the is_dir() test.
> The error message that I have in my code is printing out this error:
>
> In getListOfAnyDirectory(), we expected the function to be handed an
> address to a directory, but instead we were given this:
> ppArrangementsPublic/.
>
>
> Now, ppArrangementsPublic/ looks like a directory to me. So why is it
> failing the test?

> (snip code)


Just some shots in the dark here... try sending it
"./ppArrangementsPublic/", "./ppArrangementsPublic", or just
"ppArrangementsPublic" (no trailing slash). That might be confusing it.
Also, make sure your script is running in the current directory you think
it is.

--
-- Rudy Fleminger
-- sp@mmers.and.evil.ones.will.bow-down-to.us
(put "Hey!" in the Subject line for priority processing!)
-- http://www.pixelsaredead.com

FLEB <soon.the.sp@mmers.and.evil.ones.will.bow-down-to.us> wrote in message news:<1fxhwrw9ndoqd.4rnznd6llyhl.dlg@40tude.net>.. .
> Regarding this well-known quote, often attributed to lawrence's famous "30
> Apr 2004 16:20:44 -0700" speech:
>
> > In the function below, before I open the directory I first test to
> > make sure the address I have is, in fact, a directory. This function
> > was working fine on one web server running FreeBSD and PHP 4.06.
> > However, today I'm trying to run this software on a new server (RH
> > Linux 9, PHP 4.2.3) and the directory is failing the is_dir() test.
> > The error message that I have in my code is printing out this error:
> >
> > In getListOfAnyDirectory(), we expected the function to be handed an
> > address to a directory, but instead we were given this:
> > ppArrangementsPublic/.
> >
> >
> > Now, ppArrangementsPublic/ looks like a directory to me. So why is it
> > failing the test?
>
> > (snip code)
>
>
> Just some shots in the dark here... try sending it
> "./ppArrangementsPublic/", "./ppArrangementsPublic", or just
> "ppArrangementsPublic" (no trailing slash). That might be confusing it.
> Also, make sure your script is running in the current directory you think
> it is.


I think the problem was the capitalization, which worked on a Windows
server but not on a Linux server. Is there a way to get PHP to look
for directories in a case insensitive manner when it is on Linux?

Regarding this well-known quote, often attributed to lawrence's famous "3
May 2004 18:58:21 -0700" speech:

> FLEB <soon.the.sp@mmers.and.evil.ones.will.bow-down-to.us> wrote in message news:<1fxhwrw9ndoqd.4rnznd6llyhl.dlg@40tude.net>.. .
>> Regarding this well-known quote, often attributed to lawrence's famous "30
>> Apr 2004 16:20:44 -0700" speech:
>>
>>> In the function below, before I open the directory I first test to
>>> make sure the address I have is, in fact, a directory. This function
>>> was working fine on one web server running FreeBSD and PHP 4.06.
>>> However, today I'm trying to run this software on a new server (RH
>>> Linux 9, PHP 4.2.3) and the directory is failing the is_dir() test.
>>> The error message that I have in my code is printing out this error:
>>>
>>> In getListOfAnyDirectory(), we expected the function to be handed an
>>> address to a directory, but instead we were given this:
>>> ppArrangementsPublic/.
>>>
>>>
>>> Now, ppArrangementsPublic/ looks like a directory to me. So why is it
>>> failing the test?
>>
>>> (snip code)
>>
>>
>> Just some shots in the dark here... try sending it
>> "./ppArrangementsPublic/", "./ppArrangementsPublic", or just
>> "ppArrangementsPublic" (no trailing slash). That might be confusing it.
>> Also, make sure your script is running in the current directory you think
>> it is.
>
>
> I think the problem was the capitalization, which worked on a Windows
> server but not on a Linux server. Is there a way to get PHP to look
> for directories in a case insensitive manner when it is on Linux?

Hmm... if there isn't a function for that in PHP already, I imagine you
could iterate through a directory reading and use a case-insensitive string
match.

--
-- Rudy Fleminger
-- sp@mmers.and.evil.ones.will.bow-down-to.us
(put "Hey!" in the Subject line for priority processing!)
-- http://www.pixelsaredead.com