Newbie PHP Problem - not sure what to call this post

Hello I was hoping you may be able to help me with a problem that I am
having whilst customising a Voting Script.

I have very basic knowledge of PHP, having only learnt it for a few months
whilst at university. I thought I would have a go at editing a pre written
script but am already coming up against hurdles.

http://www.tastymota.com/lloydie/pol...=mingavote.cfg
is the poll

http://www.tastymota.com/lloydie/pollvote/mingavote.cfg is the file it takes
its information from

The problem I am having is with line 34 of the php code (I think):

printf("<img src=\"%s\">",$imageurl["image"]);

This line only takes the first letter of the filename of the image that I
wish to display, which is less than handy. I figure I am on the right track
given that I have got it to display one letter!

(There is no image called fff.jpg but I will create one when I know the
script will call it properly!)

Many thanks in advance to anyone who can end my torture



Lloydie the Tired Newbie ( 02:02 in the morning )

PS Any suggestions for a title for this problem, and therefore a better
subject for this post are greatly appreciated!!


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Lloydie wrote:

> printf("<img src=\"%s\">",$imageurl["image"]);
>
> This line only takes the first letter of the filename of the image that I
> wish to display, which is less than handy. I figure I am on the right track
> given that I have got it to display one letter!

I don't use printf myself, but having checked the API, your syntax seems
correct for what you are trying to do.

What output do you get if you add this line before your trouble line:

echo "<p>TEST: array data == ".$imageurl["image"]."</p>";

If only one letter appears after the is-equal-to symbol, then the value
stored in your $imageurl array only has one character, and you should
suspect whatever code has built the array.
--
Bob
London, UK
echo Mail fefsensmrrjyaheeoceoq\! | tr "jefroq\!" "@obe.uk"