system commands

i'm running the following php script, and where i would expect it to
create a file, test.txt, it doesn't. it isn't in the directory i am
exectuting the script in, nor can i do cat on it (not that i would
expect to, since it doesn't exist, heh):

<?php

print system("ls > test.txt");

print system("cat ls.txt");

?>

yawnmoth <terra1024@yahoo.com> writes:
> i'm running the following php script, and where i would expect it to
> create a file, test.txt, it doesn't. it isn't in the directory i am
> exectuting the script in, nor can i do cat on it (not that i would
> expect to, since it doesn't exist, heh):
>
> <?php
>
> print system("ls > test.txt");
>
> print system("cat ls.txt");

cat test.txt, surely?

> ?>

Is safe mode enabled? If so, is there an ls and a cat program in the
safe_mode_exec_dir?

--
Chris

On 13 Aug 2003 10:16:56 +0100, Chris Morris <c.i.morris@durham.ac.uk>
wrote:

>yawnmoth <terra1024@yahoo.com> writes:
>> i'm running the following php script, and where i would expect it to
>> create a file, test.txt, it doesn't. it isn't in the directory i am
>> exectuting the script in, nor can i do cat on it (not that i would
>> expect to, since it doesn't exist, heh):
>>
>> <?php
>>
>> print system("ls > test.txt");
>>
>> print system("cat ls.txt");
>
>cat test.txt, surely?

hehe - that was the problem :)

however, that doesn't help me solve the problem i was hoping it would
solve :(

if that works, then why doesn't this work?:

<?php

system("mysqldump --opt -u $dbuser --password=$dbpasswd $dbname |
gzip > $dbname" . ".gz");

print "<a href=\"$dbname" . ".gz\">Download backup</a>";

?>

ls > test.txt outputted to the directory the php script was in (as i
would expect it to), so why doesn't that? i can't find that file
anywhere, and when i run the mysqldump command through the command
line, it works just fine...