Create a class whos name is contained in a variable.

Hello all,

I would like to be able to create a new instance of a class dynamicly
from a variable name. Equivalent in java is:

ClassController vController = null;
String vClassName = "SomeControllerClass";
vController = (ClassController)Class.forName(vClassName).newInst ance();
vController.control();

Giving that each class is implementing ClassController and control()
method.

Thank you

ethorsen@gmail.com wrote:
> Hello all,
>
> I would like to be able to create a new instance of a class dynamicly
> from a variable name. Equivalent in java is:
>
> ClassController vController = null;
> String vClassName = "SomeControllerClass";
> vController = (ClassController)Class.forName(vClassName).newInst ance();
> vController.control();
>
> Giving that each class is implementing ClassController and control()
> method.
>
> Thank you

The following works for me:

$classType = 'MyClass';
$object = new $classType('constructor parameters');
var_dump($object);

is it that simple? man i love php. Thank you

mootmail-googlegroups@yahoo.com wrote:
> ethorsen@gmail.com wrote:
> > Hello all,
> >
> > I would like to be able to create a new instance of a class dynamicly
> > from a variable name. Equivalent in java is:
> >
> > ClassController vController = null;
> > String vClassName = "SomeControllerClass";
> > vController = (ClassController)Class.forName(vClassName).newInst ance();
> > vController.control();
> >
> > Giving that each class is implementing ClassController and control()
> > method.
> >
> > Thank you
>
> The following works for me:
>
> $classType = 'MyClass';
> $object = new $classType('constructor parameters');
> var_dump($object);