RE: [PHP] evaluating a variable

[snip]
Eval ($contentfunction); gave me a parse error:

Parse error: parse error in
/home/pickled/public_html/main/inc/html.php(145)
: eval()'d code on line 1

[/snip]

try to add a semicolon to the end of the variable $contentfunction =
"newsadmincontent();";