need help with gettext i18n

Hi there,

I am trying to get I18n support working on my site. To do this I have
isntalled gettext.

Somehow the translation does not work. I did everything the examples
explained, but I do stillg get en text.

Here is what I did.

1. I creaed a test file:

<?php

// I18N support information here
$language = 'de';
putenv("LANG=$language");
setlocale(LC_ALL, $language);
// Set the text domain as 'messages'
$domain = 'messages';
bindtextdomain($domain, "/home/www/mydocs/x_dev/sprachen/gettext/locale");
textdomain($domain);
echo gettext("A string to be translated would go here");

?>

2. I extracted the text via command line:
xgettext -a test.php

3. I translated it and created a mo file with poedit (editor)

4. I moved the files into a de directory


/locale
/de
/LC_MESSAGES
messages.po


When I load the php file in the browser it still gives me the entlish
language.

Has anybody an idea on what I am doing wrong?

Thank you for any help on that,

Merlin

Hi,

Tuesday, November 25, 2003, 2:25:33 AM, you wrote:
M> Hi there,

M> I am trying to get I18n support working on my site. To do this I have
M> isntalled gettext.

M> Somehow the translation does not work. I did everything the examples
M> explained, but I do stillg get en text.

M> Here is what I did.

M> 1. I creaed a test file:

M> <?php

M> // I18N support information here
M> $language = 'de';
M> putenv("LANG=$language");
M> setlocale(LC_ALL, $language);
M> // Set the text domain as 'messages'
M> $domain = 'messages';
M> bindtextdomain($domain, "/home/www/mydocs/x_dev/sprachen/gettext/locale");
M> textdomain($domain);
M> echo gettext("A string to be translated would go here");

?>>

M> 2. I extracted the text via command line:
M> xgettext -a test.php

M> 3. I translated it and created a mo file with poedit (editor)

M> 4. I moved the files into a de directory


M> /locale
M> /de
M> /LC_MESSAGES
M> messages.po


M> When I load the php file in the browser it still gives me the entlish
M> language.

M> Has anybody an idea on what I am doing wrong?

M> Thank you for any help on that,

M> Merlin


If on linux you may need to generate the right files with something like:

localedef -ci de_DE -f ISO_8859-1:1987 de_DE

Then restart apache as it caches locale info I think
--
regards,
Tom

On Mon, Nov 24, 2003 at 09:42:30PM -0800, Joffrey Leevy wrote:
:
: Would appreciate in anyone can help me.

Some more code would be helpful.

: Let's say I do a query in php, eg. $query = "select
: shed from structure"; With the mysql_fetch_array
: function and a loop I could see all the values stored
: in the column, shed, using the command: echo $shed;

$query = "select shed from structure";
$result = mysql_query($query);
while (($row = mysql_fetch_array($result)) !== false)
{
echo $row['shed'];
}

: Let's say now that I am carrying over a variable from
: a form called $form where $form = shed. I can still
: say $query = "select $form from structure"; because
: $form = shed.

Try using more variables to make life a little easier to parse:

$colname = $_FORM['form']
$query = "select {$colname} from structure";
$result = mysql_query($query);
while (($row = mysql_fetch_array($result)) !== false)
{
echo $row[$colname];
}

: The problem I have now is with the strings and how do
: I see my column values.

Use better variable names. And avoid register_globals.

Eugene Lee wrote:
> Try using more variables to make life a little easier to parse:
>
> $colname = $_FORM['form']
> $query = "select {$colname} from structure";
> $result = mysql_query($query);
> while (($row = mysql_fetch_array($result)) !== false)
> {
> echo $row[$colname];
> }
>

Very dangerous. $colname can be anything, e.g. "mysql.user.password
colname FROM mysql.user #"

On Tue, Nov 25, 2003 at 11:38:27AM +0100, Marek Kilimajer wrote:
: Eugene Lee wrote:
: >
: >Try using more variables to make life a little easier to parse:
: >
: > $colname = $_FORM['form']
: > $query = "select {$colname} from structure";
: > $result = mysql_query($query);
: > while (($row = mysql_fetch_array($result)) !== false)
: > {
: > echo $row[$colname];
: > }
: >
:
: Very dangerous. $colname can be anything, e.g. "mysql.user.password
: colname FROM mysql.user #"

I wrote it out this way because: the other user provided no source code,
I wanted to show working code, it was late and I didn't feel like adding
anything to secure against intrusions like SQL injection attacks. For
the sake of completeness, redo the first line above as:

$colname = mysql_escape_string($_FORM['form']);

Hey thanks guys. Problem solved.



--- Eugene Lee <list-php-1@fsck.net> wrote:
> On Tue, Nov 25, 2003 at 11:38:27AM +0100, Marek
> Kilimajer wrote:
> : Eugene Lee wrote:
> : >
> : >Try using more variables to make life a little
> easier to parse:
> : >
> : > $colname = $_FORM['form']
> : > $query = "select {$colname} from structure";
> : > $result = mysql_query($query);
> : > while (($row = mysql_fetch_array($result)) !==
> false)
> : > {
> : > echo $row[$colname];
> : > }
> : >
> :
> : Very dangerous. $colname can be anything, e.g.
> "mysql.user.password
> : colname FROM mysql.user #"
>
> I wrote it out this way because: the other user
> provided no source code,
> I wanted to show working code, it was late and I
> didn't feel like adding
> anything to secure against intrusions like SQL
> injection attacks. For
> the sake of completeness, redo the first line above
> as:
>
> $colname = mysql_escape_string($_FORM['form']);
>
> --
> PHP General Mailing List (http://www.php.net/)
> To unsubscribe, visit: http://www.php.net/unsub.php
>


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Eugene Lee wrote:
> On Tue, Nov 25, 2003 at 11:38:27AM +0100, Marek Kilimajer wrote:
> : Eugene Lee wrote:
> : >
> : >Try using more variables to make life a little easier to parse:
> : >
> : > $colname = $_FORM['form']
> : > $query = "select {$colname} from structure";
> : > $result = mysql_query($query);
> : > while (($row = mysql_fetch_array($result)) !== false)
> : > {
> : > echo $row[$colname];
> : > }
> : >
> :
> : Very dangerous. $colname can be anything, e.g. "mysql.user.password
> : colname FROM mysql.user #"
>
> I wrote it out this way because: the other user provided no source code,
> I wanted to show working code, it was late and I didn't feel like adding
> anything to secure against intrusions like SQL injection attacks. For
> the sake of completeness, redo the first line above as:
>
> $colname = mysql_escape_string($_FORM['form']);
>
That does not help at all, there is no character to be escaped in
"mysql.user.password colname FROM mysql.user #". The strig would have to
be in quotes, and column name cannot be in qoutes.