PHP Date()ing logic.....
This is a discussion on PHP Date()ing logic..... within the PHP General forums, part of the PHP Programming Forums category; Hi, I'm just screwing around with the date() function and timestamps but have run into a little logic problem... ...
|
|||||||
| FAQ | Members List | Calendar | Search | Today's Posts | Mark Forums Read |
10-16-2003
|
|||
|
|||
PHP Date()ing logic.....
Hi,
I'm just screwing around with the date() function and timestamps but have run into a little logic problem... So far (as you can see with the below posted code) I can manipulate days,hours and minutes...any idea on how to do months and years? Lastly the goal of this is to make take all the parameters and make 1 timestamp out of it...any ideas? or links? The code is really easy to understand and was taken from the manual but have commented it a bit none the less, so it should be real easy to understand even without executeing it. Thanks in advance. Cheers, -Ryan P.S around 20 lines of simple code below, if testing code copy and name your file t1.php..... <html><head><title> Testing Dates</title></head> <body><form type=get action=t1.php><input type=text name=m><input type=text name=h><input type=text name=d><input type=submit></form></body></html> <?php ## minutes ## echo "<br>**MINUTES**<br>"; $minutes=$_GET['m'];if(!isset($_GET['m'])){$minutes=1;} echo 'year - mo-da-hr-m - s : - : <b>$minutes</b> is set to '.$minutes.'<br>'; echo date("Y-m-d-H-i-s")." Current<br>"; echo date("Y-m-d-H-i-s",(time() + $minutes*60)); ## hours ## echo "<br><br>**HOURS**<br>"; $hours=$_GET['h'];if(!isset($_GET['h'])){$hours=1;} echo 'year - mo-da-hr-m: - : <b>$hours</b> is set to '.$hours.'<br>'; echo date("Y-m-d-H-i")." Current<br>"; echo date("Y-m-d-H-i",(time() + $hours*3600)); ## days ## echo "<br><br>**DAYS**<br>"; $days=$_GET['d'];if(!isset($_GET['d'])){$days=1;} echo 'year - mo-da-hr-m : - : <b>$days</b> is set to '.$days.'<br>'; // $days=24*3600; echo date("Y-m-d-H-i")." Current<br>"; echo date("Y-m-d-H-i",(time() + $days*(24*3600))); ?> 
|
|
10-16-2003
|
|||
|
|||
|
Re: [PHP] PHP Date()ing logic.....
If you want to manipulate months in this manner, you'll first need a month input box. Once you've got that covered, it's just a matter of using mktime() to create the appropriate date.
Edward Dudlik "Those who say it cannot be done should not interrupt the person doing it." wishy washy | www.amazon.com/o/registry/EGDXEBBWTYUU ----- Original Message ----- From: "Ryan A" <ryan@coinpass.com> To: <php-general@lists.php.net> Sent: Thursday, 16 October, 2003 15:42 Subject: [php] PHP Date()ing logic..... Hi, I'm just screwing around with the date() function and timestamps but have run into a little logic problem... So far (as you can see with the below posted code) I can manipulate days,hours and minutes...any idea on how to do months and years? Lastly the goal of this is to make take all the parameters and make 1 timestamp out of it...any ideas? or links? The code is really easy to understand and was taken from the manual but have commented it a bit none the less, so it should be real easy to understand even without executeing it. Thanks in advance. Cheers, -Ryan P.S around 20 lines of simple code below, if testing code copy and name your file t1.php..... <html><head><title> Testing Dates</title></head> <body><form type=get action=t1.php><input type=text name=m><input type=text name=h><input type=text name=d><input type=submit></form></body></html> <?php ## minutes ## echo "<br>**MINUTES**<br>"; $minutes=$_GET['m'];if(!isset($_GET['m'])){$minutes=1;} echo 'year - mo-da-hr-m - s : - : <b>$minutes</b> is set to '.$minutes.'<br>'; echo date("Y-m-d-H-i-s")." Current<br>"; echo date("Y-m-d-H-i-s",(time() + $minutes*60)); ## hours ## echo "<br><br>**HOURS**<br>"; $hours=$_GET['h'];if(!isset($_GET['h'])){$hours=1;} echo 'year - mo-da-hr-m: - : <b>$hours</b> is set to '.$hours.'<br>'; echo date("Y-m-d-H-i")." Current<br>"; echo date("Y-m-d-H-i",(time() + $hours*3600)); ## days ## echo "<br><br>**DAYS**<br>"; $days=$_GET['d'];if(!isset($_GET['d'])){$days=1;} echo 'year - mo-da-hr-m : - : <b>$days</b> is set to '.$days.'<br>'; // $days=24*3600; echo date("Y-m-d-H-i")." Current<br>"; echo date("Y-m-d-H-i",(time() + $days*(24*3600))); ?> -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
|
 |
«
Previous Thread
|
Next Thread
»
| Thread Tools | |
| Display Modes | |
Linear Mode
|
|
All times are GMT +1. The time now is 03:01 PM.
