RE: [PHP] How to access a program outside of PHP?

Mmm... okay. I tried that and nothing. Is there no way for me to determine
what the problem is? Error message some place, log file, etc? I do not
understand why this is not work. Even a simple example from the PHP manual
on system() does not work.

> I meant to do this:
>
> $szPipe = `/htdocs/gs -q
> -dNOPAUSE -dBATCH -sDEVICE=pdfwrite
> -sOutputFile=/htdocs/merged.pdf /htdocs/Sep08-113518.pdf
> /htdocs/Sep08-113523.pdf`;
>
> >>Backticks is simply the ` sign (usually the character above
> the tab).
> >>Popularly know as `hair on the ear` in my country :-)
> >>for example if you want to invoke ls from php you just type
> >>
> >>$result = `ls`;
> >>
> >>hey presto the output from ls is now in your $result variable.
> >>
> >>
> >
> >Ohhh okay. Well if you mean to do this, $szPipe =
> popen(`/htdocs/gs -q
> >-dNOPAUSE -dBATCH -sDEVICE=pdfwrite
> >-sOutputFile=/htdocs/merged.pdf /htdocs/Sep08-113518.pdf
> >/htdocs/Sep08-113523.pdf`, "r");. This does not seem change
> anything. If I
> >do this with the system() example, I get "Warning: system():
> Cannot execute
> >a blank command in /htdocs/index.php on line 14".