Re: [PHP] 4.3.3-RC1 => possible bug in in_array()?

in_array searches for a value, you suply key. This will work as you expect:

$data = array();
foreach ($this->_array_a as $key => $value) {
if (! in_array($value, $this->_array_b)
$data['added'][$key] = $this->_array_a[$key];
}

Branko F. Grac(nar wrote:

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> Hash: SHA1
>
> Hi.
>
> I've just found weird thing about in_array() function.
>
> Platform: FreeBSD 5.1/PHP 4.3.3-RC1
>
> Consider this code:
>
> $this->_array_a and $this->_array_b ARE IDENTICAL
>
> $data = array();
> foreach ($this->_array_a as $key => $value) {
> if (! in_array($key, $this->_array_b)
> $data['added'][$key] = $this->_array_a[$key];
> }
>
> Therefore after execution $data should be empty.
>
> But there is whole $this->_array_a in $data after execution...
>
> The following code works ($data is empty after execution):
> foreach ($this->_array_a as $key => $value) {
> if (! isset($this->_array_b[$key]))
> $data['added'][$key] = $this->_array_a[$key];
> }
>
> Why is this happening?
>
> Brane
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>