RE: [PHP] ereg problem?

> -----Original Message-----
> From: sven [mailto:svenie@gmx.li]
> Sent: 25 July 2003 10:35
>
> by the way, it's to complicated. the brackets [ and ] are used for
> cha-groups. you can leave them for only one char. so this
> would be the same:
> "\\n" (you have to escape the backslash with a backslash)

And then we get into the typical
double-quoted-regexp-backslash-proliferation problem -- the above will pass
\n as the regexp, which matches a newline *not* the intended literal \n. So
now you have to escape the escaped escape, to get:

"\\\\n"

Which passes \\n as the regexp, which does indeed match a literal \n !

Another way to go is to use single quotes around the regexp, since a
single-quoted string does not interpret \-expressions (except for \', of
course!) -- so this is the same regexp as above:

'\\n'

I know which I prefer, but YMMV of course!

Cheers!

Mike

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