Re: [PHP] Re: Eval var from query

The string you send to eval() must be valid PHP code. So try this..

eval( 'echo "'.$data.'";');

- Kevin


----- Original Message -----
From: "Shawn McKenzie" <nospam@mckenzies.net>
To: <php-general@lists.php.net>
Sent: Monday, July 14, 2003 1:15 PM
Subject: [php] Re: Eval var from query


> eval($data)
>
> returns Parse error: parse error, unexpected T_STRING in
> C:\apps\apache2\htdocs\test\query.php(23) : eval()'d code on line 1
>
> Thanks!
> Shawn
>
> "Shawn McKenzie" <nospam@mckenzies.net> wrote in message
> news:20030714190325.34064.qmail@pb1.pair.com...
> > How can I evaluate a var that is from a text field of a database?
> Example:
> >
> > MySQL field `name` = hi my name is $name
> >
> > In my script I have:
> >
> > $name = "Shawn";
> >
> > After fetching a query result as an associative array I have the
contents
> of
> > the `name` field in $data
> >
> > If I echo $data I get: hi my name is $name
> >
> > I would like to get: hi my name is Shawn
> >
> > TIA,
> > Shawn
> >
> >
>
>
>
> --
> PHP General Mailing List (http://www.php.net/)
> To unsubscribe, visit: http://www.php.net/unsub.php
>
>

I realized that may not make any sense. Following up the eample relates to
your original query like this..

> MySQL field `name` = hi my name is $name
> In my script I have:
> $name = "Shawn";

$data = 'hi my name is $name';
$code = 'echo "'.$data.'";';
$name = 'Shawn';
eval($code); // prints "hi may name is Shawn".

Hope that makes it more clear.

- Kevin



----- Original Message -----
From: "Kevin Stone" <kevin@helpelf.com>
To: "PHP-GENERAL" <php-general@lists.php.net>
Sent: Monday, July 14, 2003 1:23 PM
Subject: Re: [php] Re: Eval var from query


> The string you send to eval() must be valid PHP code. So try this..
>
> eval( 'echo "'.$data.'";');
>
> - Kevin
>
>
> ----- Original Message -----
> From: "Shawn McKenzie" <nospam@mckenzies.net>
> To: <php-general@lists.php.net>
> Sent: Monday, July 14, 2003 1:15 PM
> Subject: [php] Re: Eval var from query
>
>
> > eval($data)
> >
> > returns Parse error: parse error, unexpected T_STRING in
> > C:\apps\apache2\htdocs\test\query.php(23) : eval()'d code on line 1
> >
> > Thanks!
> > Shawn
> >
> > "Shawn McKenzie" <nospam@mckenzies.net> wrote in message
> > news:20030714190325.34064.qmail@pb1.pair.com...
> > > How can I evaluate a var that is from a text field of a database?
> > Example:
> > >
> > > MySQL field `name` = hi my name is $name
> > >
> > > In my script I have:
> > >
> > > $name = "Shawn";
> > >
> > > After fetching a query result as an associative array I have the
> contents
> > of
> > > the `name` field in $data
> > >
> > > If I echo $data I get: hi my name is $name
> > >
> > > I would like to get: hi my name is Shawn
> > >
> > > TIA,
> > > Shawn
> > >
> > >
> >
> >
> >
> > --
> > PHP General Mailing List (http://www.php.net/)
> > To unsubscribe, visit: http://www.php.net/unsub.php
> >
> >
>
>
>
> --
> PHP General Mailing List (http://www.php.net/)
> To unsubscribe, visit: http://www.php.net/unsub.php
>
>

Got it!

eval( '$newdata = "'.$data.'";');

Thanks!
Shawn

"Shawn McKenzie" <nospam@mckenzies.net> wrote in message
news:20030714195112.90181.qmail@pb1.pair.com...
> Thanks Kevin! That works great. It outputs: hi my name is Shawn
>
> Now if I want to assign $data to another var, let's say $newdata and have
it
> eval the $name var inside of that. How would that work?
>
> Meaning I want to $newdata = hi my name is Shawn
>
> Thanks!
> Shawn
>
> "Kevin Stone" <kevin@helpelf.com> wrote in message
> news:009801c34a3d$65aad1e0$6500a8c0@kevin...
> > The string you send to eval() must be valid PHP code. So try this..
> >
> > eval( 'echo "'.$data.'";');
> >
> > - Kevin
> >
> >
> > ----- Original Message -----
> > From: "Shawn McKenzie" <nospam@mckenzies.net>
> > To: <php-general@lists.php.net>
> > Sent: Monday, July 14, 2003 1:15 PM
> > Subject: [php] Re: Eval var from query
> >
> >
> > > eval($data)
> > >
> > > returns Parse error: parse error, unexpected T_STRING in
> > > C:\apps\apache2\htdocs\test\query.php(23) : eval()'d code on line 1
> > >
> > > Thanks!
> > > Shawn
> > >
> > > "Shawn McKenzie" <nospam@mckenzies.net> wrote in message
> > > news:20030714190325.34064.qmail@pb1.pair.com...
> > > > How can I evaluate a var that is from a text field of a database?
> > > Example:
> > > >
> > > > MySQL field `name` = hi my name is $name
> > > >
> > > > In my script I have:
> > > >
> > > > $name = "Shawn";
> > > >
> > > > After fetching a query result as an associative array I have the
> > contents
> > > of
> > > > the `name` field in $data
> > > >
> > > > If I echo $data I get: hi my name is $name
> > > >
> > > > I would like to get: hi my name is Shawn
> > > >
> > > > TIA,
> > > > Shawn
> > > >
> > > >
> > >
> > >
> > >
> > > --
> > > PHP General Mailing List (http://www.php.net/)
> > > To unsubscribe, visit: http://www.php.net/unsub.php
> > >
> > >
> >
> >
>
>