Calling functions which names are inside a variable

On Sat, 2007-08-25 at 23:46 -0600, Robert Keizer wrote:
> I am currently working on a module testing class, I can't seem to find the
> correct syntax. Here is an example of the problem:
>
> function foo( $var ){
> include $var.'.php';
> return $var(); // <!------- problem
> };
>
> foo("somefunction");
>
> In other words I am looking for a way to call a function by the value of a
> variable. I get a Call to undefined method error,
> any help would be great..

You are calling the function correctly when using a variable. Namely:

$var();

Check that the include file you want included is actually being
included. My guess is that it is not, or the function you expect to be
defined in it is not actually defined there.

Cheers,
Rob.
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I am currently working on a module testing class, I can't seem to find the
correct syntax. Here is an example of the problem:

function foo( $var ){
include $var.'.php';
return $var(); // <!------- problem
};

foo("somefunction");

In other words I am looking for a way to call a function by the value of a
variable. I get a Call to undefined method error,
any help would be great..

--
nuclearsanta@gmail.com

Thats great thanks, but it doesn't solve my problem completly, im trying to
use $output = $var(); .. which gives me an error. The $var(); works though,
so thanks for that.

Robert Keizer
""Robert Keizer"" <nuclearsanta@gmail.com> wrote in message
news:op.txnjmzww9011uo@lenovo-b0c37194...
>I am currently working on a module testing class, I can't seem to find the
>correct syntax. Here is an example of the problem:
>
> function foo( $var ){
> include $var.'.php';
> return $var(); // <!------- problem
> };
>
> foo("somefunction");
>
> In other words I am looking for a way to call a function by the value of a
> variable. I get a Call to undefined method error,
> any help would be great..
>
> --
> nuclearsanta@gmail.com

I tested this functionality.

This is working fine.



foo.php

<?

function foo( $var ){

include $var.'.php';

return $var();

};



foo("somefunction");

?>

somefunction.php

<?

function somefunction(){

echo "hello";

}

?>

Out put is hello.



You make sure that your both files are in same folder and make sure that
$var.'.php' is exist with $var function.



Warm Regards,

Sanjeev

http://www.sanchanworld.com/

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-----Original Message-----
From: Robert Keizer [mailto:nuclearsanta@gmail.com]
Sent: Sunday, August 26, 2007 11:16 AM
To: php-general@lists.php.net
Subject: [php] Calling functions which names are inside a variable



I am currently working on a module testing class, I can't seem to find the

correct syntax. Here is an example of the problem:



function foo( $var ){

include $var.'.php';

return $var(); // <!------- problem

};



foo("somefunction");



In other words I am looking for a way to call a function by the value of a

variable. I get a Call to undefined method error,

any help would be great..



--

nuclearsanta@gmail.com



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On Sun, August 26, 2007 12:46 am, Robert Keizer wrote:
> I am currently working on a module testing class, I can't seem to find
> the
> correct syntax. Here is an example of the problem:
>
> function foo( $var ){
> include $var.'.php';
> return $var(); // <!------- problem

Try this:
return ($var());

Not sure it's the answer, but suspect it might be.

And 'somefunction' *IS* defined, right?...

> };

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