MySQL PHP Code problem. Please help!

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  #1 (permalink)  
Old 09-05-2007
Cindy Chambers
 
Posts: n/a
Default MySQL PHP Code problem. Please help!

I'm stuck and trying to learn how to fix something.

I have a code written in php/html that accessed a MySQL database just fine
until my ISP upgraded. Here's the local host info:

localhost
a.. Server version: 4.1.22-standard
b.. Protocol version: 10
c.. Server: Localhost via UNIX socket
d.. MySQL charset: UTF-8 Unicode (utf8)
e..
phpMyAdmin - 2.10.0.2
a.. MySQL client version: 4.1.22
b.. Used PHP extensions: mysql
Here is my problem:

<?php

$query = "select html from UpcomingEvents where ID = ".$ID;

$result = mysql_query($query);

$row = mysql_fetch_array($result);

echo $row['html']; ?>

This worked prior to any changes. I should be able to click on September 6
Face-to-Face meeting and get that info and then click on September 8-9 MS
Bike Tour and have it pull up that info, however that's not happening.

Instead I am getting the error: Warning: mysql_fetch_array(): supplied
argument is not a valid MySQL result resource in
/home/carenclu/public_html/eventdetail.php on line 40

I can assign the ID with a specific database row number and have it pull up
that information but I need it to be dynamic and pull according to the name
of the event and give the appropriate information.

Can anyone explain to me why this is not reading anymore? I figure there is
some change with the new MySQL but I'm not experienced enough to know what
to look for. Any help will be greatly appreciated. I've got several books
and have been looking on the internet for example code but I can't find
anything that assigns and reads an ID the way this was originally set up.

Thanks,

cc







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  #2 (permalink)  
Old 09-05-2007
Herb
 
Posts: n/a
Default Re: MySQL PHP Code problem. Please help!

On Sep 5, 2:33 pm, "Cindy Chambers" <cchambers...@comcast.net> wrote:

>
> $result = mysql_query($query);


try here instead: $result = mysql_query($query) or die
(mysql_error());

to get the error msg from MySQL

the $result that you are getting back is not what is expected
>
> $row = mysql_fetch_array($result);


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  #3 (permalink)  
Old 09-05-2007
Cindy Chambers
 
Posts: n/a
Default Re: MySQL PHP Code problem. Please help!

Thank you Herb.

"Herb" <herb_k@mail.com> wrote in message
news:1189017678.946711.159380@d55g2000hsg.googlegr oups.com...
> On Sep 5, 2:33 pm, "Cindy Chambers" <cchambers...@comcast.net> wrote:
>
>>
>> $result = mysql_query($query);

>
> try here instead: $result = mysql_query($query) or die
> (mysql_error());
>
> to get the error msg from MySQL
>
> the $result that you are getting back is not what is expected
>>
>> $row = mysql_fetch_array($result);

>



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  #4 (permalink)  
Old 09-05-2007
Cindy Chambers
 
Posts: n/a
Default Re: MySQL PHP Code problem. Please help!

Well it tells me it's a syntax error so that I knew. Here's what it sent as
an error: You have an error in your SQL syntax; check the manual that
corresponds to your MySQL server version for the right syntax to use near ''
at line 1

I'm back to what is different from the old and new versions.


"Herb" <herb_k@mail.com> wrote in message
news:1189017678.946711.159380@d55g2000hsg.googlegr oups.com...
> On Sep 5, 2:33 pm, "Cindy Chambers" <cchambers...@comcast.net> wrote:
>
>>
>> $result = mysql_query($query);

>
> try here instead: $result = mysql_query($query) or die
> (mysql_error());
>
> to get the error msg from MySQL
>
> the $result that you are getting back is not what is expected
>>
>> $row = mysql_fetch_array($result);

>



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  #5 (permalink)  
Old 09-05-2007
Good Man
 
Posts: n/a
Default Re: MySQL PHP Code problem. Please help!

"Cindy Chambers" <cchambers777@comcast.net> wrote in
news:rZudnU1Y04DmkELbnZ2dnUVZ_qSonZ2d@comcast.com:

> Well it tells me it's a syntax error so that I knew. Here's what it
> sent as an error: You have an error in your SQL syntax; check the
> manual that corresponds to your MySQL server version for the right
> syntax to use near '' at line 1
>
> I'm back to what is different from the old and new versions.


Learn how to debug. You have a syntax error. It won't work in either
version.

Are you certain you know what your query is?

Before sending it to MySQL, echo it out... betcha there's a syntax error.

echo $query



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  #6 (permalink)  
Old 09-05-2007
Herb
 
Posts: n/a
Default Re: MySQL PHP Code problem. Please help!

On Sep 5, 4:11 pm, "Cindy Chambers" <cchambers...@comcast.net> wrote:
> Well it tells me it's a syntax error so that I knew.


not necessarily so, it could have been another type of problem. E.g.,
a switch from some non *nix to a *nix OS could uncover a problem with
case in a table name.

> Here's what it sent as
> an error: You have an error in your SQL syntax; check the manual that
> corresponds to your MySQL server version for the right syntax to use near ''
> at line 1
>
> I'm back to what is different from the old and new versions.


But you now do know that syntax is truly the problem.

Since it's a mystery kind of syntax problem, I'd next echo the $query
to see if it truly contains what you think it contains. e.g.:

echo ">$query<";

I'd also retype the line that assigns the string to $query, just in
case there's some weird encoding thing going on that can't be seen.
Just a shot in the dark...

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  #7 (permalink)  
Old 09-05-2007
Rik Wasmus
 
Posts: n/a
Default Re: MySQL PHP Code problem. Please help!

On Wed, 05 Sep 2007 20:33:14 +0200, Cindy Chambers
<cchambers777@comcast.net> wrote:

> I'm stuck and trying to learn how to fix something.
>
> I have a code written in php/html that accessed a MySQL database just
> fine
> until my ISP upgraded.


I'd assume it's the PHP upgrade... So not really a MySQL problem, but what
the heck :P

> Here's the local host info:
>
> localhost
> a.. Server version: 4.1.22-standard
> b.. Protocol version: 10
> c.. Server: Localhost via UNIX socket
> d.. MySQL charset: UTF-8 Unicode (utf8)
> e..
> phpMyAdmin - 2.10.0.2
> a.. MySQL client version: 4.1.22
> b.. Used PHP extensions: mysql
> Here is my problem:
>
> <?php
>
> $query = "select html from UpcomingEvents where ID = ".$ID;


Check out register_globals in the PHP documentation, and why it should be
OFF, I think this is the most likely problem after an upgrade of PHP. Use
something like:

$ID = intval($_GET['ID']); //or intval($_POST['ID']);, depending on the
method
$query = "select html from UpcomingEvents where ID = ".$ID;
--
Rik Wasmus
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  #8 (permalink)  
Old 09-08-2007
Cindy Chambers
 
Posts: n/a
Default Re: MySQL PHP Code problem. Please help!

Rik,

Thanks! That's exactly what I needed. Your code has everything reading
perfectly again. Thank you so much!

cc

"Rik Wasmus" <luiheidsgoeroe@hotmail.com> wrote in message
news:op.tx7dryow5bnjuv@metallium.lan...
On Wed, 05 Sep 2007 20:33:14 +0200, Cindy Chambers
<cchambers777@comcast.net> wrote:

> I'm stuck and trying to learn how to fix something.
>
> I have a code written in php/html that accessed a MySQL database just
> fine
> until my ISP upgraded.


I'd assume it's the PHP upgrade... So not really a MySQL problem, but what
the heck :P

> Here's the local host info:
>
> localhost
> a.. Server version: 4.1.22-standard
> b.. Protocol version: 10
> c.. Server: Localhost via UNIX socket
> d.. MySQL charset: UTF-8 Unicode (utf8)
> e..
> phpMyAdmin - 2.10.0.2
> a.. MySQL client version: 4.1.22
> b.. Used PHP extensions: mysql
> Here is my problem:
>
> <?php
>
> $query = "select html from UpcomingEvents where ID = ".$ID;


Check out register_globals in the PHP documentation, and why it should be
OFF, I think this is the most likely problem after an upgrade of PHP. Use
something like:

$ID = intval($_GET['ID']); //or intval($_POST['ID']);, depending on the
method
$query = "select html from UpcomingEvents where ID = ".$ID;
--
Rik Wasmus


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