[mrtg] Combining temp and voltages but a little complex...

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Two questions really..

I'd like to combine voltage readings and temp readings in the same graph if
at all possible.

The other half of my problem is how the values get returned, I need to do a
little math with them to get them looking right..

Here's an example from my config:
Target[temp]:
1.3.6.1.4.1.6066.2.1.3.2.1.1.1.1.4.12&1.3.6.1.4.1. 6066.2.1.3.2.1.1.1.1.4.12:public@10.8.48.20<1.3.6. 1.4.1.6066.2.1.3.2.1.1.1.1.4.12%261.3.6.1.4.1.6066 .2.1.3.2.1.1.1.1.4.12%3Apublic@10.8.48.20>*
1.8 + 32

The temp value is returned in C, so I multiply by 1.8 and add 32.


Voltage is a little more tricky..
Target[volt]:
1.3.6.1.4.1.6066.2.1.3.2.1.1.1.1.4.10&1.3.6.1.4.1. 6066.2.1.3.2.1.1.1.1.4.10:public@10.8.48.20<1.3.6. 1.4.1.6066.2.1.3.2.1.1.1.1.4.10%261.3.6.1.4.1.6066 .2.1.3.2.1.1.1.1.4.10%3Apublic@10.8.48.20>*
..01 * -1

My equipment returns the value as a negative 4 digit number. I multiply by
..01 to get my decimal point, then multiply by negative 1 to get a positive
value.

ie, -5200 becomes 52.00

TIA

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Two questions really..<br><br>I'd like to combine voltage readings and temp readings in the same graph if at all possible.<br><br>The other half of my problem is how the values get returned, I need to do a little math with them to get them looking right..<br>
<br>Here's an example from my config:<br>Target[temp]: <a href="mailto:1.3.6.1.4.1.6066.2.1.3.2.1.1.1.1.4.12 %261.3.6.1.4.1.6066.2.1.3.2.1.1.1.1.4.12%3Apublic@ 10.8.48.20">1.3.6.1.4.1.6066.2.1.3.2.1.1.1.1.4.12& amp;1.3.6.1.4.1.6066.2.1.3.2.1.1.1.1.4.12:public@1 0.8.48.20</a> * 1.8 + 32<br>
<br>The temp value is returned in C, so I multiply by 1.8 and add 32.<br><br><br>Voltage is a little more tricky..<br>Target[volt]: <a href="mailto:1.3.6.1.4.1.6066.2.1.3.2.1.1.1.1.4.10 %261.3.6.1.4.1.6066.2.1.3.2.1.1.1.1.4.10%3Apublic@ 10.8.48.20">1.3.6.1.4.1.6066.2.1.3.2.1.1.1.1.4.10& amp;1.3.6.1.4.1.6066.2.1.3.2.1.1.1.1.4.10:public@1 0.8.48.20</a> * .01 * -1<br>
<br>My equipment returns the value as a negative 4 digit number.&nbsp; I multiply by .01 to get my decimal point, then multiply by negative 1 to get a positive value.<br><br>ie, -5200 becomes 52.00<br><br>TIA<br>

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