how insert value inner array

if this work
$var0['list'] = array(
'type1' => 'val1',
'type2' => 'val2',
'type3' => 'val3'
);

is possible to have this:
$var0['list'] = array(
'type1' => 'val1',
'type2' => 'type3' => 'val2-3'
);

which is correct code ?

On 29 Apr, 12:16, nawfer <novalidsfors...@alt.al> wrote:
> if this work
> $var0['list'] = array(
> 'type1' => 'val1',
> 'type2' => 'val2',
> 'type3' => 'val3'
> );
>
> is possible to have this:
> $var0['list'] = array(
> 'type1' => 'val1',
> 'type2' => 'type3' => 'val2-3'
> );
>
> which is correct code ?

No - its syntactic and semantic garbage - and you haven't explained
what you are trying to acheive.

C.

nawfer schreef:
> if this work
> $var0['list'] = array(
> 'type1' => 'val1',
> 'type2' => 'val2',
> 'type3' => 'val3'
> );

The above is valid PHP.

>
> is possible to have this:
> $var0['list'] = array(
> 'type1' => 'val1',
> 'type2' => 'type3' => 'val2-3'
> );

That is invalid.
What do you try to accomplish by that?

What do you expect the following line will produce:
echo $var0['type2'];

???

>
> which is correct code ?

The former.

But as C pointed out, we might be of more help if you describe what you
try to store in that array.

Regards,
Erwin Moller

nawfer schrieb:

> is possible to have this:
> $var0['list'] = array(
> 'type1' => 'val1',
> 'type2' => 'type3' => 'val2-3'
> );

$var0['list'] = array(
'type1' => 'val1',
'type2' => array( 'type3' => 'val2-3' )
);

Greetings,
Thomas

--
Ce n'est pas parce qu'ils sont nombreux à avoir tort qu'ils ont raison!
(Coluche)