How to pass a function to a function?, and how to pass the variables of the function?

I'd like to write a function like:

function f(){ ... bla ...}
f_example(f);

function f_example($function_to_execute)
{...bla... $function_to_execute() ...bla....}

AND how to pass the variable of the function :

function f_example($function_to_execute($var1,$var2))
{...bla... $function_to_execute() ...bla....}

Thank you in advance for the time you'll spend for me,
Andrea.

"_andrea.l" <andrea.lorizANTISPAM@libero.it> wrote in message
news:q3NYe.16114$Jr.257637@twister2.libero.it...
> I'd like to write a function like:
>
> function f(){ ... bla ...}
> f_example(f);
>
> function f_example($function_to_execute)
> {...bla... $function_to_execute() ...bla....}
>
> AND how to pass the variable of the function :
>
> function f_example($function_to_execute($var1,$var2))
> {...bla... $function_to_execute() ...bla....}
>
> Thank you in advance for the time you'll spend for me,

Actually just like that. :) Example:
<?php

function f_example($function_to_execute, $param){
// Let's first check function exists before calling it.
if(function_exists($function_to_execute))
$function_to_execute($param);
}

$myfunction = "print";
f_example($myfunction, "Hello World");

// This runs the function print and gives
// "Hello World" to it as a parameter,
// so it prints Hello World.

?>

There is also a function for this, it's called call_user_func(), you might
want to try that, but it's much more simple to just stick the function name
into a variable and call the function with the variable...

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