fclose

Hello,
I have these lines:
$fp = "test.txt";
if ($datei = fopen ($fp, "r")) {
while (!feof ($datei)) {
$zeichen = fgetc ($datei);
echo ($zeichen);
}
fclose($fp);
}

The file is opened correctly and the content of the file is shown. But
below the content there is the error:
Warning: fclose(): supplied argument is not a valid stream resource in
........... on line 9
Where is the mistake?
Thanks Werner

*** Neudeck Werner wrote/escribió (Thu, 28 Oct 2004 13:17:01 +0200):
> $fp = "test.txt";
> if ($datei = fopen ($fp, "r")) {
[...]
> fclose($fp);

> The file is opened correctly and the content of the file is shown. But
> below the content there is the error:
> Warning: fclose(): supplied argument is not a valid stream resource in
> .......... on line 9
> Where is the mistake?

The error is that $fp is not a valid stream resource. Actually, $fp is a string. Let's check the manual:

Usage: resource fopen ( string filename, string mode [, int use_include_path [, resource zcontext]] )
Purpose: Opens file or URL

Usage: bool fclose ( resource handle )
Purpose: Closes an open file pointer

So fclose() doesn't expect a string as an argument. Can you see now where to get a resouce handle from?

--
-- Álvaro G. Vicario - Burgos, Spain
-- Thank you for not e-mailing me your questions
--

Hello,

"Alvaro G Vicario" <alvaro_QUITAR_REMOVE@telecomputeronline.com>
schrieb im Newsbeitrag
news:kym8ry84ek04.k98h53kwusdt$.dlg@40tude.net...
> *** Neudeck Werner wrote/escribió (Thu, 28 Oct 2004 13:17:01 +0200):
>> $fp = "test.txt";
>> if ($datei = fopen ($fp, "r")) {
> [...]
>> fclose($fp);
>
>> The file is opened correctly and the content of the file is shown.
>> But
>> below the content there is the error:
>> Warning: fclose(): supplied argument is not a valid stream resource
>> in
>> .......... on line 9
>> Where is the mistake?
>
> The error is that $fp is not a valid stream resource. Actually, $fp
> is a string. Let's check the manual:
>
> Usage: resource fopen ( string filename, string mode [, int
> use_include_path [, resource zcontext]] )
> Purpose: Opens file or URL
>
> Usage: bool fclose ( resource handle )
> Purpose: Closes an open file pointer
>
> So fclose() doesn't expect a string as an argument. Can you see now
> where to get a resouce handle from?
>
first: I'm a beginner so I have taken the example out of a book and
there it was written exactly like above.
Now I have modified it, like you said and it works.
Thanks, Werner

*** Neudeck Werner wrote/escribió (Thu, 28 Oct 2004 14:05:02 +0200):
> first: I'm a beginner so I have taken the example out of a book and
> there it was written exactly like above.

For some reason all programming books have typos in basic examples :)

--
-- Álvaro G. Vicario - Burgos, Spain
-- Thank you for not e-mailing me your questions
--

of course, this does'nt work because fclose wait the handle of the file open
with fopen !
if ($datei = fopen ($fp, "r")) this is wrong.....
$datei is the handle of the open file...
$handle=fopen ($fp, "r");
....... work on file
fclose($handle);

yann.


"Neudeck Werner" <w.neudeck@web.de> a écrit dans le message de news:
clqnh5$1b5$1@ngspool-d02.news.aol.com...
> Hello,
>
> "Alvaro G Vicario" <alvaro_QUITAR_REMOVE@telecomputeronline.com> schrieb
> im Newsbeitrag news:kym8ry84ek04.k98h53kwusdt$.dlg@40tude.net...
>> *** Neudeck Werner wrote/escribió (Thu, 28 Oct 2004 13:17:01 +0200):
>>> $fp = "test.txt";
>>> if ($datei = fopen ($fp, "r")) {
>> [...]
>>> fclose($fp);
>>
>>> The file is opened correctly and the content of the file is shown. But
>>> below the content there is the error:
>>> Warning: fclose(): supplied argument is not a valid stream resource in
>>> .......... on line 9
>>> Where is the mistake?
>>
>> The error is that $fp is not a valid stream resource. Actually, $fp is a
>> string. Let's check the manual:
>>
>> Usage: resource fopen ( string filename, string mode [, int
>> use_include_path [, resource zcontext]] )
>> Purpose: Opens file or URL
>>
>> Usage: bool fclose ( resource handle )
>> Purpose: Closes an open file pointer
>>
>> So fclose() doesn't expect a string as an argument. Can you see now where
>> to get a resouce handle from?
>>
> first: I'm a beginner so I have taken the example out of a book and there
> it was written exactly like above.
> Now I have modified it, like you said and it works.
> Thanks, Werner

Hello yann,

"yann kloniecki" <yklo@club-internet.fr> schrieb im Newsbeitrag
news:41811cec$0$15755$7a628cd7@news.club-internet.fr...
> of course, this does'nt work because fclose wait the handle of the
> file open with fopen !
> if ($datei = fopen ($fp, "r")) this is wrong.....
> $datei is the handle of the open file...
> $handle=fopen ($fp, "r");
> ...... work on file
> fclose($handle);
>
> yann.
>
>
> "Neudeck Werner" <w.neudeck@web.de> a écrit dans le message de news:
> clqnh5$1b5$1@ngspool-d02.news.aol.com...
>> Hello,
...........
>> "Alvaro G Vicario" <alvaro_QUITAR_REMOVE@telecomputeronline.com>
>> schrieb im Newsbeitrag
>> news:kym8ry84ek04.k98h53kwusdt$.dlg@40tude.net...
>>> *** Neudeck Werner wrote/escribió (Thu, 28 Oct 2004 13:17:01
>>> +0200):
...........

in the meantime I have understood it completeley, thanks to you and
Alvaro.
After reading your postings and studying the manual, everything works.
I only wonder, why there is such an example in a book for beginners.
And in the meantime I have realized, that it's not the only mistake in
this book (the name ist "PHP4 for dummies")
Thanks to all
Werner