parsing php inside javascript

<script language = "javascript">
foto1 = new Image;
foto1.src = "../img_models/" + <?php echo $idm_1.jpg ?> ;

it doesn't work, because of the parsing php.
Please help me!
Thanks a lot, marzia

*** Marzia Coccia wrote/escribió (Thu, 30 Oct 2003 16:13:34 +0100):
> foto1.src = "../img_models/" + <?php echo $idm_1.jpg ?> ;
>
> it doesn't work, because of the parsing php.

Parsed PHP will produce this JavaScript code:

foto1.src = "../img_models/"+foo.jpg ;

My suggestion:

foto1.src = "../img_models/<?php echo urlencode($idm_1)?>.jpg";


--
--
-- Álvaro G. Vicario - Burgos, Spain
--

Well what error does it give?
Try ending your PHP statement with a ;
Is the .jpg part of the variable name ? or do you mean to append that on the
end of the file name ?

Maybe try:

<script language = "javascript">
foto1 = new Image;
foto1.src = "../img_models/" + <?php echo ($idm_1); ?> + ".jpg";

also, im not sure if you would need quotes around the php bit so the JScript
reads it as a string (once it is parsed), but im not sure how that would
effect the parsing, maybe try

<script language = "javascript">
foto1 = new Image;
fle = <?php echo (' "' . $idm_1 . '" ' ); ?> // single quote,
double quote, single quote.
foto1.src = "../img_models/" + fle + ".jpg";

"Marzia Coccia" <m.coccia@ikaro.com> wrote in message
news:bnr99g$puf$1@fata.cs.interbusiness.it...
> <script language = "javascript">
> foto1 = new Image;
> foto1.src = "../img_models/" + <?php echo $idm_1.jpg ?> ;
>
> it doesn't work, because of the parsing php.
> Please help me!
> Thanks a lot, marzia
>
>
>

*** Alvaro G Vicario wrote/escribió (Thu, 30 Oct 2003 16:30:47 +0100):
> Parsed PHP will produce this JavaScript code:
>
> foto1.src = "../img_models/"+foo.jpg ;

Sorry, one correction:

foto1.src = "../img_models/"+foojpg ;

(given that $idm_1's value is "foo" and jpg is an undefined constant)


--
--
-- Álvaro G. Vicario - Burgos, Spain
--