Pépê wrote:
> On 20 Jun, 11:22, Captain Paralytic <paul_laut...@yahoo.com> wrote:
>> On Jun 20, 10:54 am, Pépê <josemariabar...@gmail.com> wrote:
>>
>>
>>
>>> Hi all.
>>> Im a newbie in PHP and im trying touploada file to the server.
>>> I use a form touploada pdf file and some text information about it.
>>> The client uploads the file and the system renames that file and puts
>>> all the information in the database.
>>> The problem is when the client goes again to edit the information, i
>>> always have to choose a file touploador else it will put blank the
>>> pdf column and he cant find the old one!
>>> i do a $_POST['file'] to the UPDATE statement but i think i need to do
>>> a if clause(and dont know what im going to put )...but where? i tried
>>> it in the UPDATE statement and i cant..
>> Build your update statement dynamically. This is the sort of thing,
>> but you should sanitise the $_POST input.
>>
>> if($_POST['file'])
>> $fileup = ",file = '{$_POST['file']}'";
>> else
>> $fileup = '';
>>
>> $qry = "
>> INSERT INTO fred SET
>> id = {$id},
>> info1 = '{$info1}',
>> info2 = '{$info2}
>> {$fileup}
>> ON DUPLICATE KEY UPDATE
>> info1 = '{$info1}',
>> info2 = '{$info2}'
>> {$fileup}
>> ";
>
> Hi Captain,
>
> I tried what you ve done but with the update statment:
>
> if($_POST['relatorio_pdf']){
> $fileup = ",relatorio_pdf = '{$_POST['relatorio_pdf']}'";
> }else{
> $fileup = '';
>
> if (empty($error) ) {
>
> $sql = "UPDATE relatorio SET
> relatorio_nome = '{$_POST['relatorio_nome']}',
> relatorio_ano = '{$_POST['relatorio_ano']}',
> relatorio_pdf = '$fileup',
> relatorio_activo = '{$_POST['relatorio_activo']}'
> WHERE relatorio_id = {$_GET['relatorio_id']}";
>
>
> }
> But it didnt worked..
>
> And i didnt quite understand this line: $fileup = ",relatorio_pdf =
> '{$_POST['relatorio_pdf']}'"; (why the comma, and then a variable name?
>
That's because you use UPDATE instead of INSERT.
INSERT adds a new row to the database (or, as a MySQL extension, updates
a current row). UPDATE only changes a row which already exists; it does
not add a new row.
Additionally,
$fileup = ",relatorio_pdf = '{$_POST['relatorio_pdf']}'"
is part of the SQL statement. Do you have a column named
'relatorio_pdf' in your table? Also, is the field name in your form
'relatorio_pdf'? If the answer to both is yes, then this code is
correct. Otherwise, this is a problem.
And finally, when you get your code to what Paul showed you, "it's not
working" isn't much help. What errors do you get?
--
==================
Remove the "x" from my email address
Jerry Stuckle
JDS Computer Training Corp.
jstucklex@attglobal.net
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