If you mean <p class='something'></p> then this should be okay:

$tag_regex=array(
'/\<p\>(.*?)\<\/p\> /si' => "$1",
'/\<p(\s*)class\=(*.?)\>(.*?)\<\/p\>/si' => "$2"
);
$paragraphs=preg_replace(array_keys($tag_regex),ar ray_values($tag_regex),$pa
ge);

$paragraphs will be the return value
$page is the text with all of the tags that you want to stripped

If you want, you can try the first value in the array first which detect the
<p></p>. I didn't test this, but this should be working since I also use
this kind of way to revert the phpbb code into HTML.

HTH,

Thanks,


-----Original Message-----
From: Ryan S [mailto:genphp@yahoo.com]
Sent: Wednesday, May 07, 2008 10:52 AM
To: vester_s
Cc: php php
Subject: Re: [php] Re: Re[php] gex to catch <p>s




Hey,

<clip>
$tag_regex=array(
'/\<p(\s*)\>(.*?)\<\/p\> /si' => "$1",
'/\<(\s*)(*.?)class\=(*.?)\>(.*?)\<\/(*.?)\>/si' => "$3"
);

$paragraphs=preg_replace(array_keys($tag_regex),ar ray_values($tag_regex),$pa
ge);

I am not sure what tag is that you mean on <class="something">, but in this
RE .. it should capture any <p> tags (the first element of the array) and
any tags (the second element of the array) that has attribute class on it.
</clip>

Thanks for replying!
Sorry, a bit of a typo there, i meant <p class="something">

I ran your regex but got this warning:
Warning: preg_replace() [function.preg-replace]: Compilation failed:
nothing to repeat at offset 8 in C:\xampp2\htdocs\ezee\tests\para_regex.php
on line 25


I think I ran it wrong, because although i have passed $page i dont know
where to pass the replacement texts...

Can you give me an example on how to run this or an explanation?

Thanks!
R




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