Tom Barnes wrote:
> Check out this code:
>
> // Start Code -------------
> function test_in_array($val)
> {
> $a = array('key' => $val);
> printf("in_array: %d, value:%s<BR>", in_array('key', $a), $a['key']);
> }
> test_in_array(0);
> test_in_array(1);
> // End Code ---------------
>
> The output I get is:
>
> in_array: 1, value:0
> in_array: 0, value:1
>
> Why does the second in_array() call fail???


Wrong question! The right question is:

"Why does the first in_array() call return true?"


And the answer is:

Because 'key' is converted to numeric, to 0 (zero) and 0 (zero) *is* in
the $a array.



The second in_array() call tries to find a 'key' (or 0) but fails
because the value in the array is 1.






Try specifying the third parameter to the in_array() call ...

in_array('key', $a, true)



Happy Coding :-)

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