bettina@coaster.ch wrote:
> I have 2 tables (simplified):
>
> coasters (COASTER_CODE, BREWERY_CODE, etc)
> breweries (BREWERY_CODE, BREWERY)
>
> For each brewery I want to count how many coasters are there in table
> "coasters" (up to here it works fine) and then I want to show them
> ordered by quantity (that's my problem):
>
> The following is the piece of code.
>
> $search_breweries = mysql_query("SELECT b.BREWERY_CODE, b.BREWERY,
> COUNT(c.COASTER_CODE) FROM breweries as b JOIN coasters as c ON
> b.BREWERY_CODE = c.BREWERY_CODE Group by b.BREWERY_CODE order by
> COUNT(c.COASTER_CODE) DESC ");
> $i = 0;
> while ($row = mysql_fetch_array($search_breweries, MYSQL_NUM)) {
> $mybreweries[$i][0] = $row[0];
> $mybreweries[$i][1] = $row[1];
> $mybreweries[$i][2] = $row[2];
> $i = $i + 1;
> }
> .....
> I get the following message:
> Warning: mysql_fetch_array(): supplied argument is not a valid MySQL
> result resource in....
>
> Any help will be welcomed!
>

Your query failed. Always check the return value from mysql_query:

$search_breweries = mysql_query("SELECT b.BREWERY_CODE, b.BREWERY,
COUNT(c.COASTER_CODE) FROM breweries as b JOIN coasters as c ON
b.BREWERY_CODE = c.BREWERY_CODE Group by b.BREWERY_CODE order by
COUNT(c.COASTER_CODE) DESC ");
if ($search_breweries) {
$i = 0;
while ($row = mysql_fetch_array($search_breweries, MYSQL_NUM)) {
$mybreweries[$i][0] = $row[0];
$mybreweries[$i][1] = $row[1];
$mybreweries[$i][2] = $row[2];
$i = $i + 1;
}
else
echo mysql_error();




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Jerry Stuckle
JDS Computer Training Corp.
jstucklex@attglobal.net
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