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Old 08-29-2006
calms
 
Posts: n/a
Default Reg. Dynamically populate a checkbox

HI,

First of all im vry new to PHP, i like to retrieve a value from DB,
accordingly i like to display the checkbox, either checked or not.

Now im able to retrieve the value from DB, i can show even show the
checkbox, but i cant make it checked????

Can anyone help, plzzzzzzz!!!

the Code i used to display as follows,

#Require the database class
require_once('../dbinfoinc.php');

#Get an array containing the resulting
record
$query = "SELECT * FROM event";
$result = mysql_query($query);

$num=mysql_numrows($result);
mysql_close();

$i=0;
while ($i < $num) {
if(($i % 2) == 0) { $c =
'"TableDetail"'; }
else { $c = '"TableDetail2"'; }

$event_id=mysql_result($result,$i,"event_id");

$event_name=mysql_result($result,$i,"event_name");

$event_publish=mysql_result($result,$i,"publish");
// if(($event_publish) == 0) {
$event_publish = 'No'; }
// else { $event_publish = 'YES'; }
$take_action = 'Delete';
echo "<tr>
<td Class='navText' align='center' class=$c>$event_id</td>
<td class='navText' class=$c>$event_name</td>
<td class='navText' align='center' class=$c><input type='checkbox'
name='publish' if($event_publish==1){'CHECKED';}?></td>
<td class='navText' align='center' class=$c><a
href='delete_event.php?event_id=$event_id'>$take_a ction</a></td></tr>";
$i++;
}
?>

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